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Bottle (A) contains 320ml $H_{2} O_{2}$ solution and labelled with 11.2 vol $H_{2} O_{2}$ and Bottle (B) contains 80ml $H_{2} O_{2}$ having normality 5N. Contents of bottle (A) and bottle (B) are mixed and solution is filled in bottle (C). Select the correct label for bottle (C) in terms of volume strength and gram/litre

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5.6 vol and $41.286 g L^{- 1}$

5.6 vol and 0.68 $g L^{- 1}$

14.56 vol and $44.2 g L^{- 1}$

7.28 vol and 22.1 $g L^{- 1}$

answer is A.

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Detailed Solution

$N_{m i x} = \frac{V_{1} N_{1} + V_{2} N_{2}}{V_{1} + V_{2}} \begin{array}{l} = \frac{320 \times 2 + 5 \times 80}{400} \\ = 2.6 N = 1.3 M = 44.2 g / l \\ = 14.56 volume H_{2} O_{2} \end{array}$

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