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Q.

Box A contains 25 slips of which 19 are marked Re.1 and others are marked Rs.5 each. Box B contains 50 slips of which 45 are marked Re.1 each and others are marked Rs.13 each. Slips of both boxes are poured into a third box and reshuffled. A slip is drawn at random. From the following choices, what is the probability that it is marked other than Re.1 ?


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a

19 75

b

11 75

c

64 75

d

13 75  

answer is B.

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Detailed Solution

It is given that boxes contain some slips with Re.1, Rs.5, and Rs.13.
We have to find the probability that the marked slip is other than Re.1 .
First we find the total number of slips.
n(S)=25+50
=75
19 are marked in Box A and 45 are marked in Box B as Re.1.
So, 19+45 =64 .
The number of slips that are marked other than Re.1 is,
7564=11 .
Question ImageThe probability of slips that are marked other than Re.1 is,
= 11 75 .
The probability that slip is marked other than Question Imageis 11 75 .
Hence, option 2) is correct.
 
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