B.P. of ${\mathrm{H}}_2\mathrm{O} (100°\mathrm{C})$ and ${\mathrm{H}}_2\mathrm{S}\left(-{60}^{\circ }\mathrm{C}\right)$ is explained by

Boiling point of ${\mathrm{H}}_2\mathrm{O}$ is more than that of ${\mathrm{H}}_2\mathrm{S}$ because ${\mathrm{H}}_2\mathrm{O}$ forms inter molecular hydrogen bonding while ${\mathrm{H}}_2\mathrm{S}$

does not.