Bromine is added to cold dilute aqueous solution of NaOH. The mixture is boiled. Which of the following statements is not true?

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During the reaction bromine is present in four different oxidation states

The greatest difference between the various oxidation states of bromine is 5

Disproportionation of bromine occurs during the reaction

On acidification of the final mixture bromine is formed

answer is B.

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Detailed Solution

On acidification the final mixture gives bromine:

5NaBrO+NaBrO₃+6HCl⟶6NaCl+3Br₂+3H₂O
Thus, during the reaction, bromine is present in four different oxidation states ie., zero in Br₂ ,+1 in NaBrO ,−1 in NaBr and ,+5 in NaBrO₃.

The greatest difference between various oxidation states of bromine is 6 and not 5. On acidification of the final mixture, Br2 is formed and disproportionation of Br2 occurs during the reaction giving BrO−, Br− and BrO₃⁻ ions.

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