Bromine is added to cold dilute aqueous solution of NaOH. The mixture is boiled. Which of the following statements is not true?

On acidification the final mixture gives bromine:

5NaBrO+NaBrO₃​+6HCl⟶6NaCl+3Br_2​+3H₂​O
Thus, during the reaction, bromine is present in four different oxidation states ie., zero in Br₂​ ,+1 in NaBrO ,−1 in NaBr and ,+5 in NaBrO₃​.

The greatest difference between various oxidation states of bromine is 6 and not 5. On acidification of the final mixture, Br2​ is formed and disproportionation of Br2​ occurs during the reaction giving BrO−, Br− and BrO₃⁻​ ions.