Bromine is commercially prepared from sea water by displacement reaction
${Cl}_{2} + 2 {Br}^{⊖} (aq) ⟶ 2 {Cl}^{⊖} (aq) + {Br}_{2}$
Br₂gas thus formed is dissolved into solution of Na₂CO₃ and then pure Br₂ is obtained by treatment of the solution with:

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NaOH

H₂SO₄

Ca(OH)₂

answer is B.

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Detailed Solution

$\begin{array}{l} 3 \underset{Impure}{{Br}_{2}} + 3 {Na}_{2} {CO}_{3} ⟶ 5 NaBr + {NaBrO}_{3} + 3 {CO}_{2} \end{array} \begin{array}{cc} \to_{H_{2} {SO}_{4}}^{∆} & \underset{pure}{3 {Br}_{2}} + {Na}_{2} {SO}_{4} \end{array}$

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