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Brown ring test of ${NO}_{3}^{-}$ depends upon :

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the ability of Fe2+ to form a brown compound in its Fe3+ form

the ability of Fe2+ to reduce NO3- to NO and form a brown complex in +1 oxidation state

the ability to get oxidised by NO3-ion to Fe3+ form and then form brown coloured Fe2O3 .xH2O

All of the above

answer is B.

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Detailed Solution

$\overset{+ 5}{{NO}_{3}^{-}} + 3 {Fe}^{2 +} + 4 H^{+} \overset{}{\to} 3 {Fe}^{3 +} + 2 H_{2} O + \overset{+ 2}{NO}$

${[Fe {(H_{2} O)}_{6}]}^{2 +} + NO \overset{}{\to} \underset{Brown complex}{[{Fe}^{+} {(H_{2} O)}_{5} ({NO}^{+})]} + H_{2} O$

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