Buffer solution 'A' of a weak monoprotic acid and it's sodium salt in concentration ratio X: Y has pH= $(pH)_{1}$ and buffer solution 'B' of the same acid and it's sodium salt in the concentration ratio Y: X has $pH = (pH)_{2} . If (pH)_{2} - (pH)_{1} = 1$ Unit and $(pH)_{1} + (pH)_{2} = 9.5$ Unit then:

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$\frac{X}{Y} = 2.36$

$\frac{X}{Y} = 3.162$

$p K a = 4.75$

$p K a = 5.25$

answer is A, C.

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Detailed Solution

$\begin{aligned} {pH}_{1} = p K_{a} + \log \frac{Y}{X} \\ {pH}_{2} = p K_{α} + \log \frac{X}{Y} \end{aligned}$

${pH}_{2} - {pH}_{1} = 2 \log [\frac{X}{Y}] = 1$ (given)

$\Rightarrow \frac{X}{Y} = \sqrt{10} = 3.162$

${pH}_{1} + {pH}_{2} = 2 p K_{a} = 9.5$ (given)

$\Rightarrow p K_{a} = 4.75$

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