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Bulb ‘P’ marked as 100 W, 220 V and bulb Q marked as 60 W, 110 V. The resistance ratio of P and Q is

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12 : 5

5 : 12

12 : 7

5 : 7

answer is A.

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Detailed Solution

$R = \frac{V^{2}}{P}$

$∴ R_{1} : R_{2} = \frac{V_{1}^{2}}{P_{1}} : \frac{V_{2}^{2}}{P_{2}}$ = $\frac{220^{2}}{100} : \frac{110^{2}}{60}$

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