Bulk modulus of water is 2×109 N/m2 . Change in pressure required to increase density of water by 0.1 % is :

B=∆P-∆VV=∆p∆ρρ⇒∆P=2×109×0.1100=2×106N/m2.

B=∆P-∆VV=∆p∆ρρ⇒∆P=2×109×0.1100=2×106N/m2.

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Bulk modulus of water is $2 \times 10^{9} N / m^{2}$ . Change in pressure required to increase density of water by 0.1 % is :

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$2 \times 10^{9} N / m^{2}$

$2 \times 10^{8} N / m^{2}$

$2 \times 10^{6} N / m^{2}$

$2 \times 10^{4} N / m^{2}$

answer is C.

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$B = \frac{∆ P}{\frac{- ∆ V}{V}} = \frac{∆ p}{\frac{∆ ρ}{ρ}} \Rightarrow ∆ P = 2 \times 10^{9} \times \frac{0.1}{100} = 2 \times 10^{6} N / m^{2} .$

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