Butanone oxime on reduction with $\mathrm{Na}$ / ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}$ gives

 Aldoxime and ketoxime on reduction with $\mathrm{Na}$ / ${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}$ gives primary amine. So, the product is $1^0\mathrm{amine}$

Chemical reaction

${\mathrm{CH}}_3-\underset{ }{{\mathrm{CH}}_2-\mathrm{CH}=\mathrm{N}}\left(\mathrm{OH}\right)-{\mathrm{CH}}_3\stackrel{\mathrm{Na}-{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}}{⟶}{\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CH}\left({\mathrm{NH}}_2\right)-{\mathrm{CH}}_3$