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By passing electric current, NaClO₃ is converted in to NaClO₄ according to the following equation
$\large NaCl{O_3}\, + \,{H_2}O\, \to \,NaCl{O_4} + \,{H_2}$

.How many moles of NaClO₄ will be formed when three faradays of charge is passed through NaClO₃ ?

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3.0

1.5

0.75

1.0

answer is B.

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Detailed Solution

NaCl{O_3} + {H_2}O \to NaCl{O_4} + {H_2}

In NaClO₃oxidation state of Cl is +5

In NaClO₄oxidation state of Cl is +7

Change in oxidation state of Cl is 7 - 5 = 2

1 mole of NaClO₃requires 2 mole of electrons to produce 1 mole of NaClO₄

\begin{array}{l} 2F\,\,produces\,\,\,1\,mole\,\,of\,\,NaCl{O_4}\\ 3F\,\,produces\,\, = \frac{3}{2} = 1.5\,mole\,\,of\,\,NaCl{O_4} \end{array}

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