By the addition of 0.48 mole of a base to a 1 lit. buffer solution, its pH is changed from 4.01 to 4.03. Then the buffer capacity is

Given data: It is given that by the addition of 0.48 mole of a base to a 1 lit. buffer solution, its pH is changed from 4.01 to 4.03. Then the buffer capacity is

Explanation: Buffer capacity = $\frac{numberofmolesofanacidadded}{pHchange}\frac{0.48}{4.03-4.01}$

                                                        $\frac{0.48}{0.02}$

                                                         =24

The buffer capacity is 24

Hence, the correct option is (A) 24.