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By X-ray diffraction it is found that nickel (at mass = 59 g mo1^-1), crystallizes with ccp. The edge length of the unit cell is 3.5 A. If density of Ni crystal is 9.0 g/cm³, then value of Avogadro's number from the data is :

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$6 .05 \times 10^{23}$

$6.11 \times 10^{23}$

$6.02 \times 10^{23}$

$6.023 \times 10^{23}$

answer is B.

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Detailed Solution

$\begin{array}{l} d = \frac{{zM}_{W}}{N_{A} a^{3}} \\ Z = 4, a = 3.5 \times 10^{- 8} cm, M_{w} = 59 \end{array}$

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