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$C (s) + O_{2} (g) \to {CO}_{2} (g) + 400 kJ$
$C (s) + \frac{1}{2} O_{2} (g) \to CO (g) + 100 kJ$
When coal of purity $60 %$ is allowed to burn in presence of insufficient oxygen, $60 %$ of carbon is converted into ' $CO'$ and the remaining is converted into ' ${CO}_{2}$ '. The heat generated when $0.6 kg$ of coal is burnt in KJ is

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answer is 6600.

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Detailed Solution

In 600 gm, 360 gm is carbon
216 gm (18 moles) of $C \to C O$ ,144 gm (12 moles) of $C \to C O_{2}$
Heat released $= 18 \times 100 + 12 \times 400 = 6600 K J$

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