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Q.

C0   2n2-C1   2n2+C2   2n2-···+C2n   2n2

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a

-1n.Cn   2n

b

-12n.Cn   2n

c

-1n.Cn   3n

d

-1n.Cn   n

answer is A.

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Detailed Solution

S=C0   2n2-C1   2n2+C2   2n2-···+C2n   2n2

we know that C02-C12+C22+···(-1)2 Cn2=(-1)n2 nCn2  if n is even.

 S=(-1)n  Cn  2n

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