Q.

C12H22O11+H2O(excess)C6H12O6(glucose)+C6H12O6(fructose) Rate law is expressed as

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a

r=KC12H22O11

b

r=KC12H22O11H2O

c

r=KH2O

d

r=KC12H22O11H2O2

answer is B.

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Detailed Solution

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increase in rate of reaction is maximum for the reaction having the maximum Ea. Rate doesn’t depends on excess quantity of reactant.

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C12H22O11+H2O(excess)→C6H12O6(glucose)+C6H12O6(fructose) Rate law is expressed as