$C_2{H}_{5}Br\stackrel{Na/dryether}{\to }A\underset{anhydrousAlC{l}_3}{\overset{HCl}{\to }}B\stackrel{KMn{O}_4}{\to }C.$
Regarding ‘C’ correct statement is

‘C’ is  and gives a ketone with Cu/573K.

‘C’ is  and gives a carboxylic acid containing four carbons with  $KMn{O}_4/H^{+}$

‘C’ is  and gives an aldehyde with PCC

‘C’ is  and gives immediate turbidity with HCl + anhydrous ZnCl₂