${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl} + {\mathrm{NH}}_3\left(\mathrm{excess}\right) \stackrel{\mathrm{Ethanol}}{\to }$
Major product in this reaction is

A) If C₂H₅Cl is excess then the major product is ${\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_4\stackrel{+}{\mathrm{N}}\stackrel{-}{\mathrm{Cl}}$
B) If NH₃ is excess then the major product is ${\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2$.