${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}\left(\text{excess}\right)\stackrel{{\mathrm{NH}}_3}{\to }\mathrm{A}\to \mathrm{B}\to \mathrm{C}\to \mathrm{D}\left(\text{final}\right)$. Incorrect statement

${\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}\underset{-\mathrm{HCl}}{\overset{{\mathrm{NH}}_3}{\to }}\underset{\left(\mathrm{A}\right)}{{\mathrm{C}}_2{\mathrm{H}}_5{\mathrm{NH}}_2}\underset{\mathrm{HCl}}{\overset{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}}{\to }}\underset{\left(\mathrm{B}\right)}{{\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_2}\mathrm{NH}\underset{\mathrm{HCl}}{\overset{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}}{\to }}{\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_3\mathrm{N}\stackrel{{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{Cl}}{\to }\underset{\left(\mathrm{D}\right)}{{\left({\mathrm{C}}_2{\mathrm{H}}_5\right)}_4}N{\mathrm{Cl}}^{-}$

B.P of A > B > C

because Hydrogen bonding capacity of A > B > C

Covalency of ‘N’ in ‘D’ is 4

Covalency of ‘N’ in ‘C’ is 3

(3) is false

(A), (B) contain active - H-atom but not ‘C’

‘C’ cannot give alkane with RMgX