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Q.

C2H5Cl+XC2H5OH+KCl. ‘X’ in the above reaction is

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a

Aqueous KOH

b

Moist Ag2O

c

Alcoholic KOH

d

H2O

answer is A.

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Detailed Solution

C2​H5​−Cl + aqueous KOH​→C2​H5​−OH + KCl

Alc. KOH is a dehydrohalogenating agent and it forms an alkene.

It's a basic preparation method for alkyl alcohol, in this process alkyl halide converts into alcohol in presence of aqueous KOH/NaOH.

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