C2H5OH→XCH3CHO→YC2H5OH→ZCH3COOH. X, Y and Z are respectively.

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$C_{2} H_{5} OH \overset{X}{\to} {CH}_{3} CHO \overset{Y}{\to} C_{2} H_{5} OH \overset{Z}{\to} {CH}_{3} COOH .$ X, Y and Z are respectively.

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${[A g {(N H_{3})}_{2}]}^{+}; N a B {H_{4}}_{}; {[A g {(N H_{3})}_{2}]}^{+}$

$P C C; N a B H_{4}; K M n O_{4} / H^{+}$

$P C C; Z n - H g / H C l; K M n O_{4} / O H^{-}$

$K M n O_{4} / H^{+}; L i A l H_{4}; {[A g {(N H_{3})}_{2}]}^{+}$

answer is B.

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Detailed Solution

X-PCC (controlled oxidation of $- C H_{2} O H \to - C H O$
Y- $L i A l H_{4}$ (reduction of –CO– to –CHOH–)
Z- $K M n O_{4} / H^{+}$ (1⁰ alcohol carboxylic acid)

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