C2H5OH + HCl(dry)→anhydrous ZnCl2C2H5Cl + H2O In the above reaction, the function of ZnCl2 is

to form C 2 H 5 (+) from C 2 H 5 OH

to speed up the formation of C 2 H 5 Cl

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$C_{2} H_{5} O H + H C l (d r y) \overset{a n h y d r o u s Z n C l_{2}}{\to} C_{2} H_{5} C l + H_{2} O$
In the above reaction, the function of ZnCl₂ is

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to form C₂H₅(+) from C₂H₅OH

to help the formation of Cl^-

to speed up the formation of C₂H₅Cl

to prevent the backward reaction

answer is B.

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Detailed Solution

Given data : It is given to identify the function of the $Z n C l_{2}$ in the given chemical reaction.

Explanation:

$Z n C l_{2}$ is a Lewis acid.
When oxygen and zinc establish a coordinate covalent connection in alcohol with a -OH group, oxygen gains a positive charge, and zinc gains a negative charge.
As a result, oxygen becomes a good leaving group, and the reaction progresses to producing the product.
An alkyl halide is created when the generated carbonium ion combines with chlorine in hydrochloric acid. Basically $Z n C l_{2}$ contains here a catalyzer!

Anti-Markonikoff's rule: The compound with the most carbon atoms will be the main product when the negative portion of the reagent is added to it.

The chemical reaction is as follows.

$C_{2} H_{5} O H + H C l (d r y) \overset{a n h y d r o u s Z n C l_{2}}{\to} C_{2} H_{5} C l + H_{2} O$