$C_3{H}_{8}O\stackrel{\left(O\right)}{\to }{C}_3{H}_6{O}_2$ The compound $C_3{H}_{8}O$ is a/an

In the given reaction, the number of C atoms remains the same from reactant to product and the product has two oxygen atoms. Hence, the product is an acid and the reactant is a primary alcohol.

  $\begin{array}{l}C{H}_3-C{H}_2-C{H}_{2}OH\underset{oxidation}{\overset{\left[O\right]}{\to }}C{H}_3-C{H}_2-CHO\\ \underset{oxidation}{\overset{\left[O\right]}{\to }}C{H}_3-C{H}_2-COOH\end{array}$ 

 n-Propyl alcohol                              Propionaldehyde                                       Propionic acid

            (C₃H₈O)                                                             (C₃H₆O₂)