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Q.

$C_{3} H_{8} O \to_{K_{2} {Cr}_{2} O_{7} / H^{+}}^{(O)} C_{3} H_{6} O \overset{I_{2} / NaOH}{\to} {CHI}_{3}$
In this sequence, the starting compound is

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a

2– propanol

b

Ethyl methyl ether

c

1– propanol

d

Propanal

answer is C.

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Detailed Solution

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$\underset{2 - propanol}{{CH}_{3} - CH (OH) - {CH}_{3}} \to_{K_{2} {Cr}_{2} O_{7} / H^{+}}^{(O)} \underset{Acetone}{{CH}_{3} - CO - {CH}_{3}} \overset{I_{2} / NaOH}{\to} {CHI}_{3}$

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