C3H8O (X) →573kAg(or)Cu A;A →AgNH32+ silver mirror; A →tartarateCuSO4 Red PptA→ΔOH−B; A →C6H5NHNH2 C. X, A, B, C respectively are

‘A’ cannot be ketone; ‘A’ must be aldehyde as it gives positive Tollen’s & Fehling’s test∴ ‘X’ must be a primary alcohol∴X = CH3CH2CH2OH & A = CH3CH2CHOA →ΔOH− B; CH3CH2CHO +H2CCH3CHO →OH-, ∆CH3CH2CH=CCH3CHO A →PhNHNH2 CCH3−CH2−CH = O+H2NNHph → CH3−CH2−CH = NNHph

C3H8O (X) →573kAg(or)Cu A;A →AgNH32+ silver mirror; A →tartarateCuSO4 Red PptA→ΔOH−B; A →C6H5NHNH2 C. X, A, B, C respectively are

‘A’ cannot be ketone; ‘A’ must be aldehyde as it gives positive Tollen’s & Fehling’s test∴ ‘X’ must be a primary alcohol∴X = CH3CH2CH2OH & A = CH3CH2CHOA →ΔOH− B; CH3CH2CHO +H2CCH3CHO →OH-, ∆CH3CH2CH=CCH3CHO A →PhNHNH2 CCH3−CH2−CH = O+H2NNHph → CH3−CH2−CH = NNHph

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$\begin{array}{l} C_{3} H_{8} O (X) \to_{573 k}^{Ag (or) Cu} A; \\ A \overset{{(Ag {({NH}_{3})}_{2})}^{+}}{\to} silver mirror; A \to_{tartarate}^{{CuSO}_{4}} Red Ppt \\ A \to_{Δ}^{{OH}^{-}} B; A \overset{C_{6} H_{5} {NHNH}_{2}}{\to} C . X, A, B, C respectively are \end{array}$

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$\begin{array}{l} {CH}_{3} {CH}_{2} {CH}_{2} OH, {CH}_{3} {COCH}_{3}, {({CH}_{3})}_{2} C = CH - CO - {CH}_{3}, {({CH}_{3})}_{2} C = N NH - ph \end{array}$

$\begin{array}{l} {CH}_{3} {CHOHCH}_{3}, {CH}_{3} {COCH}_{3}, {({CH}_{3})}_{2} C = CH - CO - {CH}_{3}, {({CH}_{3})}_{2} C = N NH - ph \end{array}$

$\begin{array}{l} {CH}_{3} {CH}_{2} {CH}_{2} OH, {CH}_{3} {CH}_{2} CHO {, CH}_{3} {CH}_{2} CH=C ({CH}_{3}) CHO , {CH}_{3} {CH}_{2} CH = NNHPh \end{array}$

$\begin{array}{l} {CH}_{3} {CHOHCH}_{3}, {CH}_{3} {CH}_{2} CHO {, CH}_{3} {CH}_{2} CH=C ({CH}_{3}) CHO , {CH}_{3} {CH}_{2} CH = NNHPh \end{array}$

answer is C.

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Detailed Solution

‘A’ cannot be ketone; ‘A’ must be aldehyde as it gives positive Tollen’s & Fehling’s test
$∴$ ‘X’ must be a primary alcohol
$∴ X = {CH}_{3} {CH}_{2} {CH}_{2} OH & A = {CH}_{3} {CH}_{2} CHO$