${\mathrm{C}}_4{\mathrm{H}}_8 \left(\mathrm{A}\right) \stackrel{\mathrm{Hcl}}{\to } \mathrm{B} \stackrel{1 \mathrm{mole} \mathrm{of} {\mathrm{NH}}_3}{\to } \mathrm{C} +\stackrel{ {\mathrm{NaNO}}_{2 }+ \mathrm{HCl} }{\to }+ {\mathrm{H}}_2\mathrm{O}$

If ' $\mathrm{A}$ ' on reductive ozonalysis produced 2 moles of ethanal, the then correct statement is

$$\begin{gathered} {\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-{\mathrm{CH}}_3\stackrel{\mathrm{HCl}}{\to } {\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CHCl}-{\mathrm{CH}}_3 \\ \left(\mathrm{A}\right) \left(\mathrm{B}\right) \end{gathered}$$

$$\begin{gathered} {\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CHCl}-{\mathrm{CH}}_3\stackrel{1 \mathrm{mole} {\mathrm{NH}}_3}{\to } {\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CH}\left({\mathrm{NH}}_2\right)-{\mathrm{CH}}_3 \\ \left(\mathrm{B}\right) \left(\mathrm{C}\right) \end{gathered}$$

$$\begin{gathered} {\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CH}\left({\mathrm{NH}}_2\right)-{\mathrm{CH}}_3\underset{ }{\overset{ }{\underset{0-5{}^0\mathrm{C} ,{\mathrm{H}}_2\mathrm{O}}{\overset{{\mathrm{NaNO}}_2+\mathrm{HCl}}{\to }} { }_{ }}}{\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CH}\left({\mathrm{N}}_2\mathrm{Cl}\right)-{\mathrm{CH}}_3 \\ \left(\mathrm{C}\right) \left(\mathrm{D}\right) \end{gathered}$$

            ${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CH}\left({\mathrm{N}}_2\mathrm{Cl}\right)-{\mathrm{CH}}_3$  $\stackrel{{\mathrm{H}}_2\mathrm{O}}{\to }$${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{CH}\left(\mathrm{OH}\right)-{\mathrm{CH}}_3$