$\begin{array}{l} C_{6} H_{5} {NH}_{2} + Na {NO}_{2} + 2 HCl \overset{273 K}{\to} (A) \to_{(ii) {NaNO}_{2}, Cu, Δ}^{(i) {HBF}_{4}} (B) \end{array}$
The products A, B in above sequence of reactions respectively are

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$C_{6} H_{5} N O_{2}, C_{6} H_{5} N H_{2}$

$C_{6} H_{5} N_{2} Cl, C_{6} H_{5} F$

$C_{6} H_{5} N_{2} Cl, C_{6} H_{5} {NO}_{2}$

$C_{6} H_{5} N O_{2}, C_{6} H_{5} C l$

answer is A.

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Detailed Solution

$\begin{array}{l} C_{6} H_{5} {NH}_{2} + {NaNO}_{2} + 2 HCl \overset{273 K}{\to} C_{6} H_{5} N_{2} Cl \to_{(ii) {NaNO}_{2}, Cu, Δ}^{(i) {HBF}_{4}} C_{6} H_{5} {NO}_{2} \end{array}$

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