C6H5CH2OH⟶HBrX⟶KCNY⟶H3O+ΔZ .What are X, Y and Z ?

Chemical Reaction Sequence ExplanationStarting compound: C6H5CH2OHSequence of reactions:C6H5CH2OH → HBr → X → KCN → Y → H3O+, Δ → ZIdentification of X, Y and ZCompoundChemical FormulaNameXC6H5CH2BrBenzyl bromideYC6H5CH2CNBenzyl cyanideZC6H5CH2COOHPhenylacetic acidExplanation1. Benzyl alcohol reacts with hydrogen bromide (HBr) to form benzyl bromide (X).2. Benzyl bromide undergoes nucleophilic substitution with potassium cyanide (KCN) to give benzyl cyanide (Y).3. Benzyl cyanide on acidic hydrolysis in the presence of heat (H3O+, Δ) gives phenylacetic acid (Z).

C6H5CH2OH⟶HBrX⟶KCNY⟶H3O+ΔZ .What are X, Y and Z ?

Chemical Reaction Sequence ExplanationStarting compound: C6H5CH2OHSequence of reactions:C6H5CH2OH → HBr → X → KCN → Y → H3O+, Δ → ZIdentification of X, Y and ZCompoundChemical FormulaNameXC6H5CH2BrBenzyl bromideYC6H5CH2CNBenzyl cyanideZC6H5CH2COOHPhenylacetic acidExplanation1. Benzyl alcohol reacts with hydrogen bromide (HBr) to form benzyl bromide (X).2. Benzyl bromide undergoes nucleophilic substitution with potassium cyanide (KCN) to give benzyl cyanide (Y).3. Benzyl cyanide on acidic hydrolysis in the presence of heat (H3O+, Δ) gives phenylacetic acid (Z).

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$C_{6} H_{5} {CH}_{2} OH \overset{HBr}{⟶} X \overset{KCN}{⟶} Y \underset{Δ}{\overset{H_{3} O^{+}}{⟶}} Z$ .What are X, Y and Z ?

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$\begin{aligned} X : C_{6} H_{5} {CH}_{2} {CH}_{2} Br \\ Y : C_{6} H_{5} {CH}_{2} {CH}_{2} CN \\ Z : C_{6} H_{5} {CH}_{2} {CO}_{2} H \end{aligned}$

$\begin{array}{l} X : C_{6} H_{5} CHO, Y : C_{6} H_{5} CH = CH - CH, \\ Z : C_{6} H_{5} {CH}_{2} {CO}_{2} H \end{array}$

$\begin{array}{l} X : C_{6} H_{5} {CH}_{2} Br, Y : C_{6} H_{5} {CH}_{2} CN \\ Z : C_{6} H_{5} {CH}_{2} {CO}_{2} H \end{array}$

$\begin{array}{l} X : C_{6} H_{5} {CH}_{2} Br, Y : C_{6} H_{5} {CH}_{2} NC \\ Z : C_{6} H_{5} {CO}_{2} H \end{array}$

answer is C.

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Detailed Solution

Chemical Reaction Sequence Explanation

Starting compound: C₆H₅CH₂OH

Sequence of reactions:

C₆H₅CH₂OH → HBr → X → KCN → Y → H₃O⁺, Δ → Z

Identification of X, Y and Z

Compound	Chemical Formula	Name
X	C₆H₅CH₂Br	Benzyl bromide
Y	C₆H₅CH₂CN	Benzyl cyanide
Z	C₆H₅CH₂COOH	Phenylacetic acid

Explanation

1. Benzyl alcohol reacts with hydrogen bromide (HBr) to form benzyl bromide (X).
2. Benzyl bromide undergoes nucleophilic substitution with potassium cyanide (KCN) to give benzyl cyanide (Y).
3. Benzyl cyanide on acidic hydrolysis in the presence of heat (H₃O⁺, Δ) gives phenylacetic acid (Z).