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Q.

C6H6+3H2⇌C6H12, ∆H=-204 kJ ; Heat of hydrogenation of each C=C (assumed to be) in benzene is [in KJ]

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a

-68

b

-34

c

-612

d

-204

answer is A.

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Detailed Solution

Benzene contains 3 C=C bonds

Heat\; of\; hydrogenation\; of\; each (C=C) =\frac{total\Delta H}{3}

                                                                                

C=C bond enthalpy=-2043=-68 kJ/mole ;

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