$C_{6} H_{6} + C O + H C l \to_{}^{A n h y d r o u s A l C l_{3}} X + H C l$
Compound X is

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$C_{6} H_{5} C H_{3}$

$C_{6} H_{5} C H_{2} C l$

$C_{6} H_{5} C H O$

$C_{6} H_{5} C O O H$

answer is C.

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Detailed Solution

$C_{6} H_{6} + C O + H C l \to_{}^{A n h y d r o u s A l C l_{3}} C_{6} H_{5} C H O + H C l$

In the reaction described above, benzaldehyde and hydrochloric acid are the end products. A derivative of benzene and an aromatic substance, benzoaldehyde. The chemical can be referred to as benzaldehyde since the aldehyde group is joined to the benzene ring.

Hence , the correct option is (C) $C_{6} H_{5} C H O$

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