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Q.

${CaC}_{2} \overset{Hydrolysis}{⟶} X \overset{\overset{Redhot}{Fetube}}{\to}$ Y. Regarding X and Y, the correct statement is

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a

Same percentage composition of elements by weight

b

Their empirical formula also different

c

Contain same hybridized carbon atoms

d

Contains same number of $π$ -bonds

answer is B.

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Detailed Solution

${CaC}_{2} \overset{H_{2} O}{⟶} C_{2} H_{2} \underset{tube}{\overset{Hot}{⟶}} C_{6} H_{6}$ They both have ratio of carbon as 1:1., having same percent composition.

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