${CaCO}_{3 (s)} ⇌ {CaO}_{i s)} + {CO}_{2 (g)}$ which of the following
expression is correct
Or
For the equilibrium ${CaCO}_{3 (s)} ⇌ {CaO}_{(s)} + {CO}_{2 (g)}$ the
equilibrium constant is represented by the following form

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$K_{P} = (P_{CaO} + P_{{CO}_{2}} / P_{{CaCO}_{3}})$

$K_{p} = P_{{CO}_{2}}$

$K_{P} \times (P_{CaO} \times P_{{CO}_{2}}) \cdot {P_{CaCO}}_{3}$

$\frac{K_{p} [CaO] {CO}_{2}]}{[{CaCO}_{3}]}$

answer is B.

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Detailed Solution

$\begin{array}{l} {CaCO}_{3 (s)} ⇌ {CaO}_{(s)} + {CO}_{2 (g)} \\ K_{P} = P_{{CO}_{2}} \end{array}$

Solid molecule does not have partial pressure so in

calculation of $K_{p} only P_{{CO}_{2}}$ is applicable.

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