${\text{CaCO}}_{\text{3}}\left(s\right)\to \text{CaO\hspace{0.17em}}\left(s\right){\text{+ CO}}_{\text{2}}\left(g\right)$  According to the equation

A) Products	1) ${\text{CO}}_{\text{2}}$
B) GMW of one mole lime stone	2) 56 g
C) GMW of one mole CaO	3) ${\text{CaO \& CO}}_2$
D) The gas produced in above equation is	4) 100 g

The Chemical reaction for the decomposition of lime stone is

           ${\text{CaCO}}_3\left(s\right)\to \text{CaO\hspace{0.17em}}\left(s\right)+{\text{CO}}_{\text{2}}\left(g\right)$

            Reactants                 Products      

            GMW of one mole of lime stone , ${\text{CaCO}}_3$is ,

            $1(\text{Ca)\hspace{0.17em}+\hspace{0.17em}1(C)\hspace{0.17em}+\hspace{0.17em}\hspace{0.17em}3(O)}=1\left(40\right)+1\left(12\right)+3\times \left(16\right)$

                                    $=40+12+48$

                                    $=100\text{g}$

            The gas produced in the decomposition of lime stone is ${\text{CO}}_{\text{2}}$.

            Gram molar mass of CaO $=1\left(40\right)+1\left(16\right)=56\text{g}$