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Q.

Cadmium amalgam is prepared by electrolysis of a solution of CdCl₂, using a mercury cathode. How long should a current of 4 A be passed in order to prepare 10% by weight of Cd in Cd-Hg amalgam on cathode of 4.5 g Hg? (atomic wt. of Cd : 112)

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a

400 sec

b

215.40 sec

c

861.6 sec

d

430.8 sec

answer is B.

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Detailed Solution

10 g Cd should deposit on 90 g Hg.
Weight of Cd required for 4.5 g of Hg cathode
$W = \frac{10}{90} \times 4 .5 = 0 .5 g; {Cd}^{2} + 2 e^{-} \to Cd \begin{array}{ll} ∴ & 0.5 = \frac{112 \times 4 \times t}{2 \times 96500} \\ \Rightarrow & t = 215 .40 \sec \end{array}$

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Cadmium amalgam is prepared by electrolysis of a solution of CdCl2, using a mercury cathode. How long should a current of 4 A be passed in order to prepare 10% by weight of Cd in Cd-Hg amalgam on cathode of 4.5 g Hg? (atomic wt. of Cd : 112)