Calcium carbonate decomposes on heating according to the following equation
${CaCO}_{3 (s)} \Leftrightarrow {CaO}_{(s)} + {CO}_{2 (g)}$
The number of moles of ${CO}_{2}$ obtained by the decomposition of $50 g {CaCO}_{3}$ is

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$\frac{3}{2}$

$\frac{5}{2}$

$\frac{1}{2}$

answer is C.

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Detailed Solution

${CaCO}_{3 (s)} \Leftrightarrow {CaO}_{(s)} + {CO}_{2 (g)}$

100g----------1 mole ${CO}_{2}$

50g---------?

$\frac{50}{100} = \frac{1}{2} moles$

On decomposition of $50 gr {CaCO}_{3} O . 5 moles of {CO}_{2} obtained$

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