Calcium carbonate decomposes on heating to give calcium oxide and carbon dioxide. How much volume of CO₂ will be obtained by thermal decomposition of 50 g of CaCO₃?

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44 L

1 L

11.2 L

22.4 L

answer is B.

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Detailed Solution

$\underset{100 g}{{CaCO}_{3}} \to CaO + \underset{22.4 L}{{CO}_{2}}$
100 g of CaCO₃ at STP gives 22.4 L of CO₂
50 g of CaCO₃ will produce $\frac{22 .4}{100} \times 50 = 11 .2 L of {CO}_{2}$

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