Calcium imide on hydrolysis will give gas (B) which on oxidation by bleaching powder gives gas (C). Gas (C) on reaction with magnesium gives compound (D). (D) on hydrolysis gives again gas (B). (B), (C) and (D) are respectively

When calcium imide is hydrolyzed, it produces a gas B, which bleaching powder can then oxidise to produce a gas C. Gas C reacts with magnesium to produce compound D, which then undergoes hydrolysis to produce gas B once more. B, C, and D are hence ${\mathrm{NH}}_3$. ${\mathrm{NH}}_3,{\mathrm{N}}_2$ and ${\mathrm{Mg}}_3{\mathrm{N}}_2$ respectively.

These are the responses:

$\mathrm{CaNH}+{\mathrm{H}}_2\mathrm{O}$

           $\downarrow$

$\mathrm{Ca}(\mathrm{OH}{)}_2+\underset{\left(B\right)}{{\mathrm{NH}}_3}\underset{\left[\mathrm{O}\right]}{\overset{{\mathrm{CaOCl}}_2}{\to }}\underset{\left(\mathrm{C}\right)}{{\mathrm{N}}_2}\underset{ }{\overset{{\mathrm{Mg}}_2}{\to }}\underset{\left(\mathrm{D}\right)}{{\mathrm{Mg}}_3{\mathrm{N}}_2}$

${\mathrm{Mg}}_3{\mathrm{N}}_2 +{\mathrm{H}}_2\mathrm{O}--------->\mathrm{Mg}{\left(\mathrm{OH}\right)}_2+{\mathrm{NH}}_3.$