Q.

Calculate the percent dissociation of H2S(g) if 0.1 mole of H2S is kept in 0.4lit vessel at 1000 K for the reaction 2H2S(g)2H2(g)+S2(g) . Value of kc is 1.0×106

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a

0.2

b

2

c

1

d

0.1

answer is A.

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Detailed Solution

2H2S(g)2H2(g)+S2(g)                

Molar conc. at equilibrium =0.1x0.4x0.4x0.8

Kc=[H2]2[S2][H2S]2x=2×103

%x=2×1030.1×100=2

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