Calculate change in Gibb’s free energy (in cal., Magnitude only) at 300 K for a reaction $A ⇌ B$ if A is at 5 bar pressure and B is at 10 bar pressure and $Δ H^{0} = - 8$ K Cal/mole, $Δ S^{0} = + 2$ Cal/mole Kelvin.[Given: R=2 Cal/mole K, ln 4=1.4]

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

answer is 8180.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$Δ G^{0} = Δ H^{0} - T Δ S^{0} = - 8000 - 300 \times 2 = - 8600 C a l / m o l e$

$\begin{array}{l} Δ G = Δ G^{0} + R T \ln θ \\ = - 8600 + 2 \times 300 \ln 2 \\ = - 8600 + 600 \times 0.7 \\ = - 8600 + 420 = 8180 A n s \end{array}$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test