Calculate equilibrium constant (in multiples of 10^–80) when sodium reduces Aluminium oxide to aluminium at 
$298\mathrm{K}.{\mathrm{\Delta G}}_{\mathrm{f}}^0\text{ of }{\mathrm{Na}}_2{\mathrm{O}}_{\left(\mathrm{s}\right)}\text{ at }298\mathrm{K}=-377\mathrm{KJ}{\mathrm{mole}}^{-1}\text{ and }{\mathrm{\Delta G}}_{\mathrm{f}}^0\text{ of }{\mathrm{A\ell }}_2{\mathrm{O}}_3\text{ at }298\mathrm{K}=-1582$ $\mathrm{KJ}{\mathrm{mole}}^{-1}\text{ ) }$