Calculate heat released (in kJ) when 2 moles of gaseous methane undergoes combustion in a rigid vessel of volume 50 litres causing a change in pressure from 10 bar to 2 bar at 300 K.
[Useful data :
$\begin{aligned} Δ H_{f} H_{2} O = - 280 kJ / mole \\ Δ H_{f} {CO}_{2} = - 390 kJ / mole \\ Δ H_{f} {CH}_{4} = - 70 kJ / mole] \end{aligned}$

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answer is 1720.

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Detailed Solution

$\begin{array}{l} {CH}_{4} + 2 O_{2} ⟶ {CO}_{2} + 2 H_{2} O \\ Δ H = - 2 \times 280 - 390 + 70 = - 880 \\ Δ U = Δ H - V Δ P \\ = - 2 \times 880 + \frac{400 \times 100}{1000} \\ = - 1720 kJ / mole \end{array}$

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