Calculate packing fraction of $CsCI$ structure.
Use : $\sqrt{3} = 1.732, π = \frac{22}{7}$
Assume no distortion in the crystal Express your answer after multiplying your answer with 1050 $∴$ If your answer is $\frac{1}{1.05}$ you should write 1000.

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answer is 700.

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Detailed Solution

$Packing fraction = \frac{2 X Total vol . of sphere}{Total vol . of unit cell}$

$= \frac{2 \times \frac{4}{3} π r^{3}}{{(\frac{4}{\sqrt{3}} r)}^{3}}$

$= \frac{2 \times \frac{4}{3} \times \frac{22}{7} \times r^{3}}{\frac{64}{3 \times 1.7} \times r^{3}}$

$= \frac{22}{7} \times \frac{1.7}{8} = \frac{37.5}{56} = \frac{1}{1.5} \times 1050$

$= 700$

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