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Q.

Calculate Power Factor for Choke Coil with R and L Given

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Detailed Solution

To calculate the power factor of a choke coil, you need three values:

  1. The coil's resistance (R), in Ohms (Ω).
  2. The coil's inductance (L), in Henrys (H).
  3. The frequency (f) of the AC supply, in Hertz (Hz).

The calculation is a three-step process:

Step 1: Calculate the Inductive Reactance (XL)
This is the opposition the coil's inductance presents to the alternating current.
XL = 2π f L

Step 2: Calculate the Total Impedance (Z)
This is the total opposition of the coil, combining its resistance and inductive reactance.
Z = √(R2 + XL2)

Step 3: Calculate the Power Factor (cos φ)
The power factor is the ratio of the resistance to the total impedance.
cos φ = R / Z

Substituting the previous steps, the full formula is:

cos φ = R / √(R2 + (2π f L)2)

Example:
A choke coil has a resistance R = 10 Ω and an inductance L = 0.1 H. It is connected to a 50 Hz supply.

  1. XL = 2π(50)(0.1) ≈ 31.42 Ω
  2. Z = √(102 + 31.422) = √(100 + 987.2) = √(1087.2) ≈ 32.97 Ω
  3. cos φ = 10 / 32.97 ≈ 0.303

The power factor of this choke coil is approximately 0.303 (lagging).

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