Calculate resonance energy of  $C_6{H}_6\left(g\right)$.Given: $\Delta H_f\left[C_6{H}_6\left(g\right)\right]=-360kJmo{l}^{-1};\Delta H_{sub}\left[C_{\left(graphite\right)}\right]=716kJmo{l}^{-1}$ ;  

$B.E_{H-H}=437kJ\text{\hspace{0.17em}}mo{l}^{-1};B.E_{C=C}=620kJmo{l}^{-1};B.E_{C-C}=340kJmo{l}^{-1};B.E_{C-H}=490kJmo{l}^{-1}$

$For{C}_6{H}_6$

$6C\left(s\right)+3H_2\left(g\right)\to C_6{H}_6;\Delta H_{\exp }=-360kJmo{l}^{-1}$

$\Delta H_{cal}=-\left[3(C-C)+3(C=C)+6(C-H)\right]+\left[6C_{S\to g}+3(H-H)\right]$

$=-[3\times 340+3\times 620+6\times 490]+[6\times 716+3\times 437]$

$=-5820+5607=-213kJmo{l}^{-1}$

Resonance energy = Exp. $\Delta H_f-$ calculated  $\Delta H_f$
 $=-360-(-213)=-360+213=-147kJmo{l}^{-1}$