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Calculate $Δ S$ for 3 moles of a diatomic ideal gas which is heated and compressed from 298k and 1 bar to 596k and 4 bar

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$+ 14.7 {calk}^{- 1}$

$6.3 {calk}^{- 1}$

$- 14.7 {calk}^{- 1}$

$- 4.9 {calk}^{- 1}$

answer is D.

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Detailed Solution

$Δ s = n C p R \ln \frac{T_{2}}{T_{1}} + n R \ln \frac{P_{1}}{P_{2}}$

$= 3 x \frac{7}{2} x 2 X \ln \frac{596}{298} + 3 x 2 X \ln \frac{1}{4}$ = 6.3 Cal/K

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