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Calculate solubility (mol/m³) of saturated solution of Ag₃PO₄, if its dilute aqueous solution at ? K has a vapour pressure of 730 mm Hg and vapour pressure of pure H₂O is 740 mm Hg at TK.

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149.7

250.1

190.2

355.2

answer is B.

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Detailed Solution

$\frac{P^{\circ} - P}{P} = \frac{i \times m \times 18}{1000} (m \approx M) \frac{740 - 730}{730} = \frac{4 \times M \times 18}{1000} M = 0.1902 mol / L or 190.2 mol / m^{3}$

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