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Q.

Calculate the accelerating potential that must be imparted to a proton beam to give it an effective wavelength of 0.005nm.

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a

10.4 volt

b

1.23 volt

c

13.6 volt

d

32.82 volt

answer is B.

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Detailed Solution

Velocity of proton is calculated as:

v=h =6.626×10-341.627×10-27×10-9 =7.93×104 meter sec-1 ...(I)

Relation between Q (charge), Mass (m), accelerating potential (V), and velocity (v).

12mv2=Q.Vv=2.Q.Vm =2×1.602×10-191.627×10-27×V ...(II)

Equate (I) and (II)

7.93×104 meter sec-1=2×1.602×10-191.627×10-27×VV=32.82 volt

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