Calculate the amount of Ni needed in the Mond's process given belowNi+4CO→Ni(CO)4If CO used in this process is obtained through a process, in which 6g of carbon is mixed with 44g of CO2⋅[Ni=58.7]

Cn=612 (LR)+CO24444→2CO- WNi=1×14×58.7=14.675g

Calculate the amount of Ni needed in the Mond's process given belowNi+4CO→Ni(CO)4If CO used in this process is obtained through a process, in which 6g of carbon is mixed with 44g of CO2⋅[Ni=58.7]

Cn=612 (LR)+CO24444→2CO- WNi=1×14×58.7=14.675g

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Calculate the amount of Ni needed in the Mond's process given below
$Ni + 4 CO \to Ni (CO)_{4}$
If CO used in this process is obtained through a process, in which 6g of carbon is mixed
with 44g of ${CO}_{2} \cdot [Ni = 58.7]$

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58.7g

28g

14.675g

29.35 g

answer is A.

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$\underset{\underset{(LR)}{n = \frac{6}{12}}}{C} + \underset{\frac{44}{44}}{{CO}_{2}} \to \underline{2 CO} W_{Ni} = 1 \times \frac{1}{4} \times 58.7 = 14.675 g$

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Calculate the amount of Ni needed in the Mond's process given belowNi+4CO→Ni(CO)4If CO used in this process is obtained through a process, in which 6g of carbon is mixed with 44g of CO2⋅[Ni=58.7]

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Calculate the amount of Ni needed in the Mond's process given below
$Ni + 4 CO \to Ni (CO)_{4}$
If CO used in this process is obtained through a process, in which 6g of carbon is mixed
with 44g of ${CO}_{2} \cdot [Ni = 58.7]$