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Q.

Calculate the coulomb force (in N) between two alpha particles separated by a distance of $3.2 \times 10^{- 15} m$ in air

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answer is 90.

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Detailed Solution

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$F = \frac{1}{4 π \in_{0}} \frac{q_{1} q_{2}}{r^{2}}$

$= 9 \times 10^{9} \times \frac{2 e \times 2 e}{{(3.2 \times 10^{- 15})}^{2}}$

$\frac{= 9 \times 10^{9} \times 4 \times {(1.6 \times 10^{- 19})}^{2}}{3.2 \times 3.2 \times 10^{- 30}} = 90 N$

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