Calculate the electrode potential at  ${25}^{0}C$  of  $C{r}_2{O_7}^{-2}/C{r}^{+3}$electrode at  $P^{OH}=11$  in a solution of  $0.01$M both in $C{r}^{+3}$and  $C{r}_2{O_7}^{-2}$,  EMF of the cell is $C{r}_2{O_7}^{-2}+14H^{\oplus }+6e^{-}\to 2C{r}^{+3}+7H_{2}O,E^O=1.33V$

 $C{r}_2{O_7}^{-2}+14H^{\oplus }+6e^{-}\to 2C{r}^{+3}+7H_{2}O,E^O=1.33v$
 $0.01 {10}^{-3}0.01$
 $P^{OH}=11$
 $P^H=3$
 $\left[H^{+}\right]={10}^{-3}M$
E cell     $=E^{0}cell-\frac{0.0591}{6}\log \frac{{\left[c{r}^{+3}\right]}^2}{\left[c{r}_2{O_7}^{-2}\right]{\left[H^{+}\right]}^{14}}$
  $=1.33-\frac{0.0591}{6}\log \frac{{\left[0.01\right]}^2}{\left(0.01\right){\left({10}^{-3}\right)}^{14}}=0.936V$